This explaination was in regard to red/cyan 3D pair but it seems to
work for cross-eyed stuff too.
From my post back on 5/14/99 (I was making sure I had Grimdude's
explaination right).
//---------------------------------------------------------
I think I did it right, it seemed to work. But in case I 
just got lucky;
let me make sure I have your directions straight. So it's:

1. Find the distance between the camera location and look_at.
   ie. if the look_at is <0,0,0> and my camera location is
   <0,.5,-4> then the result I want is along z which = 4 .

2. Divide the result of step 1. by 11.8(12.0 respectively).
   I get 0.33893 

3. Divide step 2. by 2(the number 2, Not step2).
   which = 0.1694915 

4. The result of step 3. is added to the x value in the camera
   location for the right.tga. And subtracted for the left.tga.
   left.tga = camera{ location<-0.1694915,.5,-4>
   right.tga= camera{ location<0.1694915,.5,-4>


-- 
Phil
...coffee?...yes please! extra sugar,extra cream...Thank you.

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